USE AdventureWorks;
GO
SELECT VendorID, [164] AS Emp1, [198] AS Emp2, [223] AS Emp3, [231] AS Emp4, [233] AS Emp5
FROM
(SELECT PurchaseOrderID, EmployeeID, VendorID
FROM Purchasing.PurchaseOrderHeader) p
PIVOT
(
COUNT (PurchaseOrderID)
FOR EmployeeID IN
( [164], [198], [223], [231], [233] )
) AS pvt
ORDER BY pvt.VendorID;
VendorID Emp1 Emp2 Emp3 Emp4 Emp5
1 4 3 5 4 4
2 4 1 5 5 5
3 4 3 5 4 4
4 4 2 5 5 4
5 5 1 5 5 5
SELECT PurchaseOrderID, EmployeeID, VendorID
FROM PurchaseOrderHeader;
--Create the table and insert values as portrayed in the previous example.
CREATE TABLE pvt (VendorID int, Emp1 int, Emp2 int,
Emp3 int, Emp4 int, Emp5 int);
GO
INSERT INTO pvt VALUES (1,4,3,5,4,4);
INSERT INTO pvt VALUES (2,4,1,5,5,5);
INSERT INTO pvt VALUES (3,4,3,5,4,4);
INSERT INTO pvt VALUES (4,4,2,5,5,4);
INSERT INTO pvt VALUES (5,5,1,5,5,5);
GO
--Unpivot the table.
SELECT VendorID, Employee, Orders
FROM
(SELECT VendorID, Emp1, Emp2, Emp3, Emp4, Emp5
FROM pvt) p
UNPIVOT
(Orders FOR Employee IN
(Emp1, Emp2, Emp3, Emp4, Emp5)
)AS unpvt;
GO
VendorID Employee Orders
1 Emp1 4
1 Emp2 3
1 Emp3 5
1 Emp4 4
1 Emp5 4
2 Emp1 4
2 Emp2 1
2 Emp3 5
2 Emp4 5
2 Emp5 5
...
请注意，UNPIVOT 并不完全是 PIVOT 的逆操作。PIVOT 会执行一次聚合，从而将多个可能的行合并为输出中的单个行。而 UNPIVOT 不会重现原始表值表达式的结果，因为行已经被合并了。另外，UNPIVOT 的输入中的空值不会显示在输出中，而在执行 PIVOT 操作之前，输入中可能有原始的空值。